Step of Proof: ax_choice |
12,41 |
|
Inference at * 1 1 1 1 1 1
Iof proof for Lemma ax choice:
1. A : Type
2. B : Type
3. Q : A
B

4. g : x:A
y:B
Q(x,y)
5. x : A
6. y1 : B
7. y2 : Q(x,y1)
8. <y1, y2> = g(x)
Q(x,<y1, y2>.1)
by ((AbReduce 0)
CollapseTHEN ((Auto_aux (first_nat 1:n) ((first_nat 1:n),(first_nat 4:n
C)) (first_tok :t) inil_term)))
C.